Precalculus / Calculus — Exponential Functions

Hyperbolic Functions: Definitions, Identities & Derivatives

Hyperbolic functions — sinh, cosh, tanh and their reciprocals — are defined from the exponential function and mirror the properties of trig functions, but for the unit hyperbola instead of the unit circle. They arise everywhere from hanging cables to special relativity.

The Six Hyperbolic Functions

All six functions are defined in terms of and e⁻ˣ. The three primary functions are sinh, cosh, and tanh; the other three are their reciprocals.

sinh x

pronounced "sinch" or "shine"

sinh x = (eˣ − e⁻ˣ) / 2

Domain:(−∞, ∞)
Range:(−∞, ∞)

sinh(0) = 0

Odd: sinh(−x) = −sinh(x)

Unbounded S-curve through origin. Grows exponentially for large |x|.

cosh x

pronounced "cosh"

cosh x = (eˣ + e⁻ˣ) / 2

Domain:(−∞, ∞)
Range:[1, ∞)

cosh(0) = 1

Even: cosh(−x) = cosh(x)

U-shaped catenary. Minimum value 1 at x = 0. Never negative.

tanh x

pronounced "tanch" or "than"

tanh x = sinh x / cosh x

Domain:(−∞, ∞)
Range:(−1, 1)

tanh(0) = 0

Odd: tanh(−x) = −tanh(x)

Bounded S-curve (sigmoid). Horizontal asymptotes at y = ±1.

csch x

pronounced "coseech"

csch x = 1 / sinh x

Domain:x ≠ 0
Range:(−∞, 0) ∪ (0, ∞)

csch(0) undefined

Odd: csch(−x) = −csch(x)

Two branches, asymptotes at x = 0 and y = 0. Like a hyperbolic cosecant.

sech x

pronounced "seech"

sech x = 1 / cosh x

Domain:(−∞, ∞)
Range:(0, 1]

sech(0) = 1

Even: sech(−x) = sech(x)

Bell-shaped curve. Maximum value 1 at x = 0. Approaches 0 as x → ±∞.

coth x

pronounced "coth"

coth x = cosh x / sinh x

Domain:x ≠ 0
Range:(−∞, −1) ∪ (1, ∞)

coth(0) undefined

Odd: coth(−x) = −coth(x)

Two branches outside (−1, 1). Vertical asymptote x = 0, horizontal asymptotes y = ±1.

Key Identities

Hyperbolic identities closely parallel trig identities — but watch the signs. The fundamental identity has a minus where trig has a plus.

cosh²x − sinh²x = 1

Trig analog: cos²x + sin²x = 1

The fundamental hyperbolic identity. Notice the minus sign (not plus).

tanh²x + sech²x = 1

Trig analog: tan²x + sec²x = — (not analogous)

Divide the fundamental identity by cosh²x. Compare: 1 − tanh²x = sech²x.

coth²x − csch²x = 1

Trig analog: cot²x + csc²x = csc²x − 1... different form

Divide the fundamental identity by sinh²x.

sinh(2x) = 2 sinh x cosh x

Trig analog: sin(2x) = 2 sin x cos x

Double angle for sinh. Exactly the same form as the trig double angle.

cosh(2x) = cosh²x + sinh²x

Trig analog: cos(2x) = cos²x − sin²x

Double angle for cosh. Note the plus sign — not minus as in trig.

cosh(x+y) = cosh x cosh y + sinh x sinh y

Trig analog: cos(x+y) = cos x cos y − sin x sin y

Addition formula for cosh. Again: plus sign where trig has minus.

Osborn's Rule

A quick way to convert trig identities to hyperbolic ones: replace every trig function with its hyperbolic counterpart, and flip the sign of every product of two sinh terms. For example, cos(x+y) = cos x cos y − sin x sin y becomes cosh(x+y) = cosh x cosh y + sinh x sinh y (the − sin·sin product becomes + sinh·sinh).

Trig vs. Hyperbolic Functions: Comparison

The parallel structure is real — but the differences matter, especially the lack of periodicity and the sign flip in the derivative of cosh.

PropertyTrig FunctionsHyperbolic Functions
Definition basisUnit circle x² + y² = 1Unit hyperbola x² − y² = 1
Periodic?Yes (period 2π for sin/cos)No — no periodicity
Parity: cos/coshcos is evencosh is even
Parity: sin/sinhsin is oddsinh is odd
Pythagorean identitycos²x + sin²x = 1cosh²x − sinh²x = 1
Derivative of cos/cosh−sin x+sinh x
Derivative of sin/sinhcos xcosh x
Boundedness of tanh/tantan is unbounded (has asymptotes)tanh is bounded: (−1, 1)
cosh rangecos range: [−1, 1][1, ∞) — always ≥ 1
Double angle (cos/cosh)cos(2x) = cos²x − sin²xcosh(2x) = cosh²x + sinh²x

Graphs of the Primary Hyperbolic Functions

y = sinh x

Domain: (−∞, ∞)
Range: (−∞, ∞)
Key points: (0, 0), (1, ≈1.18), (−1, ≈−1.18)

Increasing through all reals. Odd function symmetric about origin. Grows like eˣ/2 for large x, like −e⁻ˣ/2 for large negative x.

y = cosh x

Domain: (−∞, ∞)
Range: [1, ∞)
Key points: (0, 1) minimum, (1, ≈1.54), (−1, ≈1.54)

U-shaped catenary. Even function symmetric about y-axis. Minimum at (0,1). Never below 1. Resembles a parabola near origin but grows exponentially.

y = tanh x

Domain: (−∞, ∞)
Range: (−1, 1)
Key points: (0, 0), horizontal asymptotes y = ±1

Bounded S-curve (sigmoid). Odd function. Increases from −1 to 1. Steepest at origin (slope = sech²(0) = 1). Never reaches ±1.

Important: Unlike trig functions, sinh and cosh have no maximum — they grow without bound. cosh is always ≥ 1 (it never goes below 1), while sinh takes all real values. tanh is the only primary hyperbolic function that is bounded.

Derivatives of Hyperbolic Functions

The key difference from trig: d/dx[cosh x] = +sinh x, not −sinh x. All other derivatives follow the same sign pattern as their trig counterparts.

f(x)f ′(x)Trig analogNote
sinh xcosh xsin x → cos xSame form as trig.
cosh xsinh xcos x → −sin xPositive! Not negative like trig.
tanh xsech²xtan x → sec²xSame structure as trig.
csch x−csch x coth xcsc x → −csc x cot xSame form as trig.
sech x−sech x tanh xsec x → sec x tan xMinus sign; trig has plus.
coth x−csch²xcot x → −csc²xSame form as trig.

Watch out on exams

The most common error is writing d/dx[cosh x] = −sinh x by analogy with cosine. It is +sinh x. The sign difference traces back to the minus in the fundamental identity cosh²x − sinh²x = 1.

Inverse Hyperbolic Functions

Each inverse hyperbolic function can be written exactly as a natural logarithm. This is possible because sinh and cosh are defined with exponentials — solving, for instance, y = sinh x for x means solving an equation in eˣ, which gives a quadratic in eˣ.

arcsinh(x)

also: sinh⁻¹(x)

ln(x + √(x² + 1))

Domain: (−∞, ∞)

Defined for all real x. The +1 under the radical means the expression inside ln is always positive.

arccosh(x)

also: cosh⁻¹(x)

ln(x + √(x² − 1))

Domain: [1, ∞)

Requires x ≥ 1. At x = 1: arccosh(1) = ln(1 + 0) = 0. Only the principal (positive) branch.

arctanh(x)

also: tanh⁻¹(x)

(1/2) ln((1 + x)/(1 − x))

Domain: (−1, 1)

Requires |x| < 1. Vertical asymptotes at x = ±1. Useful in integration of 1/(1 − x²).

arccsch(x)

also: csch⁻¹(x)

ln(1/x + √(1/x² + 1))

Domain: x ≠ 0

Can be written as arcsinh(1/x). Defined for all nonzero real x.

arcsech(x)

also: sech⁻¹(x)

ln(1/x + √(1/x² − 1))

Domain: (0, 1]

Can be written as arccosh(1/x). Requires 0 < x ≤ 1.

arccoth(x)

also: coth⁻¹(x)

(1/2) ln((x + 1)/(x − 1))

Domain: |x| > 1

Requires |x| > 1. Related to arctanh by arccoth(x) = arctanh(1/x).

Why the logarithm forms matter in calculus

The logarithmic forms let you evaluate and differentiate inverse hyperbolic functions without a special table. For example, d/dx[arcsinh x] = d/dx[ln(x + √(x²+1))] = 1/√(x²+1). Similarly, d/dx[arctanh x] = 1/(1−x²). These are standard integration results: arcsinh x arises from ∫ 1/√(x²+1) dx, and arctanh x from ∫ 1/(1−x²) dx.

Real-World Applications

Catenary Curve

A flexible, inextensible chain hanging under gravity assumes the shape y = a·cosh(x/a). This appears in suspension bridges, power lines, spider webs, and the iconic Gateway Arch in St. Louis (an inverted weighted catenary).

Special Relativity

The Lorentz boost (changing between inertial reference frames) can be parametrized with rapidity φ so that v/c = tanh φ, γ = cosh φ, and γv/c = sinh φ. This makes velocity composition simply additive in rapidity.

Heat and Wave Equations

Hyperbolic functions appear as solutions to linear ODEs and PDEs with constant coefficients. For example, sinh and cosh solve y″ = y (compare: sin and cos solve y″ = −y). This makes them natural in boundary value problems.

Integration Formulas

∫ 1/√(x²+1) dx = arcsinh(x) + C; ∫ 1/√(x²−1) dx = arccosh(x) + C; ∫ 1/(1−x²) dx = arctanh(x) + C for |x| < 1. These parallel the trig substitution results and are often simpler to write.

Neural Networks

tanh(x) is a classic activation function in neural networks. Its output is bounded in (−1, 1), it is smooth and differentiable everywhere, and its derivative sech²(x) is easy to compute. It is related to the sigmoid by: tanh(x) = 2·sigmoid(2x) − 1.

Differential Geometry

On a surface of constant negative curvature (hyperbolic geometry), the analog of circles uses cosh and sinh in the metric. The tractrix — the curve traced by a point on a taut string as the other end moves along a line — involves hyperbolic functions in its arc length formula.

Worked Examples

Example 1: Evaluate sinh(0) and cosh(0)

  1. 1.Use the definitions directly.
  2. 2.sinh(0) = (e⁰ − e⁻⁰)/2 = (1 − 1)/2 = 0/2 = 0.
  3. 3.cosh(0) = (e⁰ + e⁻⁰)/2 = (1 + 1)/2 = 2/2 = 1.
  4. 4.These are the baseline values: the point (cosh 0, sinh 0) = (1, 0) lies on the unit hyperbola x² − y² = 1.
Answer: sinh(0) = 0, cosh(0) = 1

Example 2: Evaluate cosh(ln 2)

  1. 1.Use the definition: cosh(ln 2) = (e^(ln 2) + e^(−ln 2))/2.
  2. 2.Simplify: e^(ln 2) = 2 and e^(−ln 2) = 1/2.
  3. 3.So cosh(ln 2) = (2 + 1/2)/2 = (5/2)/2 = 5/4.
Answer: cosh(ln 2) = 5/4

Example 3: Prove cosh²x − sinh²x = 1

  1. 1.Write out cosh²x − sinh²x using the definitions.
  2. 2.cosh²x = ((eˣ + e⁻ˣ)/2)² = (e²ˣ + 2 + e⁻²ˣ)/4.
  3. 3.sinh²x = ((eˣ − e⁻ˣ)/2)² = (e²ˣ − 2 + e⁻²ˣ)/4.
  4. 4.Subtract: cosh²x − sinh²x = [(e²ˣ + 2 + e⁻²ˣ) − (e²ˣ − 2 + e⁻²ˣ)]/4 = 4/4 = 1. ✓
Answer: cosh²x − sinh²x = 1 (verified)

Example 4: Find d/dx[sinh(3x²)]

  1. 1.Apply the chain rule: d/dx[sinh(u)] = cosh(u) · u′, where u = 3x².
  2. 2.u′ = 6x.
  3. 3.So d/dx[sinh(3x²)] = cosh(3x²) · 6x = 6x cosh(3x²).
Answer: 6x cosh(3x²)

Example 5: If sinh x = 3/4, find cosh x

  1. 1.Use the identity cosh²x − sinh²x = 1.
  2. 2.cosh²x = 1 + sinh²x = 1 + (3/4)² = 1 + 9/16 = 25/16.
  3. 3.Since cosh x ≥ 1 > 0 for all real x, take the positive root.
  4. 4.cosh x = √(25/16) = 5/4.
Answer: cosh x = 5/4

Frequently Asked Questions

What is the difference between hyperbolic functions and trigonometric functions?

Trigonometric functions are defined using the unit circle (x² + y² = 1), while hyperbolic functions are defined using the unit hyperbola (x² − y² = 1). Both share similar identities — compare cos²x + sin²x = 1 with cosh²x − sinh²x = 1 — but hyperbolic functions are not periodic and grow without bound. sinh is an odd function and cosh is an even function, just like sin and cos, but cosh never goes negative and sinh is unbounded.

Why is cosh called the catenary function?

A hanging flexible chain or cable under uniform gravity forms a curve called a catenary. This shape is described by the equation y = a·cosh(x/a), where a is a constant related to the tension and weight of the cable. The word 'catenary' comes from the Latin 'catena' meaning chain. The Gateway Arch in St. Louis is an upside-down catenary shape (technically a weighted catenary). Engineers and architects use cosh to model cables, power lines, and arched structures.

What is sinh(0) and cosh(0)?

sinh(0) = (e⁰ − e⁻⁰)/2 = (1 − 1)/2 = 0. cosh(0) = (e⁰ + e⁻⁰)/2 = (1 + 1)/2 = 1. These are analogous to sin(0) = 0 and cos(0) = 1 in trigonometry. The point (cosh(0), sinh(0)) = (1, 0) lies on the unit hyperbola x² − y² = 1, just as (cos(0), sin(0)) = (1, 0) lies on the unit circle.

How do you find the derivative of tanh(x)?

The derivative of tanh(x) is sech²(x). You can derive this using the quotient rule: tanh(x) = sinh(x)/cosh(x), so d/dx[tanh x] = (cosh x · cosh x − sinh x · sinh x)/cosh²x = (cosh²x − sinh²x)/cosh²x = 1/cosh²x = sech²x. This is analogous to d/dx[tan x] = sec²x in trigonometry.

What are the formulas for inverse hyperbolic functions?

Inverse hyperbolic functions can be expressed as logarithms: arcsinh(x) = ln(x + √(x² + 1)) for all real x; arccosh(x) = ln(x + √(x² − 1)) for x ≥ 1; arctanh(x) = (1/2)ln((1 + x)/(1 − x)) for |x| < 1. These logarithmic forms are useful in integration — for example, ∫ 1/√(x²+1) dx = arcsinh(x) + C = ln(x + √(x²+1)) + C.

Is tanh bounded like regular tangent?

No — regular tangent has vertical asymptotes and is unbounded, while tanh is bounded between −1 and 1. As x → +∞, tanh(x) → 1; as x → −∞, tanh(x) → −1. The graph of tanh is a smooth S-curve (sigmoid) with horizontal asymptotes at y = ±1. This bounded, S-shaped behavior makes tanh useful as an activation function in neural networks and as a model for saturation effects in physics.

How do hyperbolic functions appear in special relativity?

In special relativity, the Lorentz transformation — which relates observations between two inertial frames moving at relative velocity v — can be written using hyperbolic functions. If we define rapidity φ by tanh(φ) = v/c, then the Lorentz factor is cosh(φ) and the velocity factor is sinh(φ). This hyperbolic parametrization makes the composition of velocities equivalent to adding rapidities, which is simpler than using the relativistic velocity addition formula directly.

Why does d/dx[cosh x] = sinh x (not −sinh x)?

This is one of the key differences from trig: d/dx[cos x] = −sin x, but d/dx[cosh x] = +sinh x. You can verify from the definitions: d/dx[cosh x] = d/dx[(eˣ + e⁻ˣ)/2] = (eˣ − e⁻ˣ)/2 = sinh x. The positive sign arises because both eˣ and e⁻ˣ contribute positively to the derivative of cosh, whereas in cosine the oscillating nature introduces the negative sign.

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